Software Tools in Haskell: charreplace

replace chars by strings on stdin

Posted on 2016-02-27 by nbloomf
Tags: software-tools-in-haskell, literate-haskell

This page is part of a series on Software Tools in Haskell.

This post is literate Haskell; you can load the source into GHCi and play along.


As usual, we start with some imports.

-- sth-charreplace: replace chars with strings on stdin
module Main where

import System.Environment (getArgs, getProgName)
import System.Exit (exitSuccess, exitFailure)
import System.IO (hPutStrLn, stderr)

See also the Backslash module.

import Lib.Backslash (bsUnEsc)

The program charreplace is a companion to translit and requires no new machinery.

main :: IO ()
main = do
  args <- getArgs

  (notflag,from,to) <- do
    let
      (flag,rest) = case args of
        ("--not":xs) -> (True,xs)
        xs           -> (False,xs)

    (from,to) <- case rest of
      [as] -> case readCharSeq (bsUnEsc as) of
        Just xs -> return (xs, "")
        Nothing -> argError
      [as,bs] -> case readCharSeq (bsUnEsc as) of
        Just xs -> return (xs, bsUnEsc bs)
        Nothing -> argError
      otherwise -> argError

    return (flag,from,to)

  let
    remove = case notflag of
      False -> filter (not . (`elem` from))
      True  -> filter (`elem` from)

  let
    replace = case notflag of
      False -> concatMap
                 (\x -> if x`elem`from then to else [x])
      True  -> concatMap
                 (\x -> if x`elem`from then [x] else to)

  case to of
    ""        -> charFilter remove
    otherwise -> charFilter replace

  exitSuccess


argError :: IO a
argError = reportErrorMsgs
  [ "usage:"
  , "  charreplace [SOURCE] [TARGET] -- replace each char in SOURCE with TARGET string"
  , "  charreplace [REMOVE]          -- remove each char in REMOVE string"
  , "option:"
  , "  --not  : invert selection (e.g. replace all *except* SOURCE)"
  ] >> exitFailure

It may seem like overkill to split the functionality from translit and charreplace just to make the interface more consistent. But note that charreplace naturally does something we couldn’t have done if the two were rolled together, at least not without making the interface even more inconsistent: charreplace naturally replaces characters by strings, not just characters. This is not a trivial distinction; for example, if we have a text file which uses unix-style line endings (\n) and want to convert them to Windows-style line endings (\r\n) we can do this with

charreplace "\n" "\r\n"

I can’t think of a way to do this with translit alone.

Old Stuff

data CCLine
  = CCLine [String]
  deriving (Show)


-- apply a map to stdin
charFilter :: (String -> String) -> IO ()
charFilter f = do
  xs <- getContents
  putStr $ f xs


-- write list of messages to stderr
reportErrorMsgs :: [String] -> IO ()
reportErrorMsgs errs = do
  name <- getProgName
  sequence_ $ map (hPutStrLn stderr) $ ((name ++ " error"):errs)


unfoldrMaybe :: (b -> Maybe (Maybe (a,b))) -> b -> Maybe [a]
unfoldrMaybe f x = case f x of
  Nothing -> Nothing
  Just Nothing -> Just []
  Just (Just (a,b)) -> do
    as <- unfoldrMaybe f b
    Just (a:as)


data CharSeq
  = Single Char
  | Range  Char Char
  deriving (Show)

readCharSeq :: String -> Maybe String
readCharSeq = fmap charSeqsToList . readCharSeqs . bsUnEsc
  where
    charSeqsToList :: [CharSeq] -> String
    charSeqsToList = concatMap charSeqToList
      where
        charSeqToList (Single x)  = [x]
        charSeqToList (Range x y) = enumFromTo x y
    
    readCharSeqs :: String -> Maybe [CharSeq]
    readCharSeqs = unfoldrMaybe firstCharSeq
      where
        firstCharSeq :: String -> Maybe (Maybe (CharSeq, String))
        firstCharSeq ""      = Just Nothing
        firstCharSeq [x]     = Just (Just (Single x, ""))
        firstCharSeq ('-':_) = Nothing
        firstCharSeq [x,y]   = Just (Just (Single x, [y]))
        firstCharSeq (x:y:z:xs) = case y of
          '-' -> Just (Just (Range x z, xs))
          otherwise -> Just (Just (Single x, y:z:xs))